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TextStyle>@ Times New RomanNormal>@Times New Roman Heading 1>@ Arial Heading 2>@Times New Roman Heading 3 >@ Arial Paragraph >@ ArialList >@ ArialIndent >@Times New RomanTitle >@Times New RomanSubtitle font_style_listO font_styleP  VariablesTimes New Roman@P  ConstantsTimes New Roman@P TextArial@P Greek VariablesSymbol@P User 1Arial@P User 2 Courier New@P User 3Arial@P User 4Times New Roman@P User 5Times New Roman@P User 6Arial@P User 7Times New Roman@P SymbolsSymbol@P Current Selection FontArial@P Undefined Font@P HeaderArial@P FooterArial@P Rotated Math FontTimes New Roman TextRegion* docRegionGshpBoxUx#=x87YY CharacterMap-RangeMap;EE421 Unbalanced Line Example ChrPropMap7 ParPropMap9 RangeElem< ParPropData: RangeData=EmbedMap1<LinkMap/<LinkData0@ Heading 1Times New Roman*@UYlh`-Define transformation79<:1</<0@NormalTimes New Roman eqRegionB@U(~u7Dtree@ p@@ @@da@@@@t1 @@!@@d e"@@ #@@t"1j$@@"%@@@$&@@t%2'@@%\p(@@$3)@B@Ul*@@ p+@@ *,@@d+A1-@@p+.@@0-/@@0A.0@@0A/1@@0A02@@0A13@@0A24@@0A35@@0A46@@0A57@@@68@@69@@d8a:@@82;@@5a<@@41=@@3a>@@2?@@d>a@@@@>2@A@@11@B@@01@C@@/1@D@@.1@E*@U4Xjj-Define Constants:79@F<@G:1@H</@I<@J0@NormalTimes New Roman @K@B@U(:?@L@@ p@M@@ @L@N@@d@M\r@O@@@M@P@@5@@O@Q@@t@P100@R@@@Pohm@S@@@Om@T@B@U @U@@ p@V@@ @U@W@@d@Vfreq@X@@5@V@Y@@t@X60@Z@@@XHz@[@B@U((Q@@7@\@@ p@]@@ @\@^@@d@]\mo@_@@5@]@`@@@@_@a@@@@`@b@@t@a4@c@@@a\p@d@@@`@e@@t@d10@f@@K@d@g@@@f7@h@@@_@i@@d@hH@j@@@hm@k@B@U'OR)@@l@@ p@m@@ @l@n@@d@mIcons@o@@@m@p@@d@o\mo@q@@@o@r@@t@q2@s@@@q\p@t@B@U0h+@u@@ p@v@@ @u@w@@d@vCarsonsResistConst@x@@5@v@y@@5@@x@z@@t@y9.869@{@@@y@|@@t@{10@}@@K@{@~@@@}7@@@@x@@@d@ohm@@@@@@@d@m@@@@Hz@@B@Ui7@@@ p@@@ @@@@d@ De_const@@@@@@@t@2160@@@@@@@@@@@@d@ft@@@@@@@d@Hz@@@@0.5@@@@@@@p@@@@@@@@@d@ohm@@@@m@@@@0.5@*@U(8(HH&&-@Compute the series impedance matrix for the line configuration of Figure P4.4 where the conductor is 336,400 CM, 26/7 Strand ACSR. 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The is an approximation of the 6x6 matrix approach. 79Bt<Bu:1Bv</Bw<Bx0@NormalTimes New Roman By@B@U8uBz@@ pB{@@ BzB|@@dB{ RsbundleB}@@{B{B~@@B}B@@dB~GMR3B@@B~Da1a2B@B@U@  P B@@ pB@@ BB@@dBLperlength_altB@@BB@@dBIconsB@@pBB@@0BB@@0ABB@@0ABB@@0ABB@@0ABB@@0ABB@@0ABB@@0ABB@@0ABB@@@BB@@BB@@dBlnB@@pBB@@BB@@dBDeB@@B RsbundleB@@BB@@dBlnB@@pBB@@BB@@dBDeB@@BDbcB@@BB@@dBlnB@@pBB@@BB@@dBDeB@@BDacB@@BB@@dBlnB@@pBB@@BB@@dBDeB@@BDbcB@@BB@@dBlnB@@pBB@@BB@@dBDeB@@B RsbundleB@@BB@@dBlnB@@pBB@@BB@@dBDeB@@BDabB@@BB@@dBlnB@@pBB@@BB@@dBDeB@@BDacB@@BB@@dBlnB@@pBB@@BB@@dBDeB@@BDabB@@BB@@dBlnB@@pBB@@BB@@dBDeB@@B RsbundleB*@U(1 D (@ o-@SThe resistance matrix must also be modified since there are now parallel conductors7S9SB ~8 C=@@ pC>@@ C=C?@@dC>DmC@@@C>CA@@p@C@CB@@CACC@@@CBCD@@dCCDabCE@@CCDbcCF@@CBDacCG@@C@CH@@tCG1CI@@CG3CJ@B@UX* > u8 CK@@ pCL@@CKCM@@dCLDmCN@@CLCO@@+@CN@XCP@@CNftCQ@B@UXP y ph CR@@ pCS@@ CRCT@@dCSL1CU@@CSCV@@dCUIconsCW@@CUCX@@dCWlnCY@@pCWCZ@@CYC[@@dCZDmC\@@CZGMRC]@B@UPX  gp C^@@ pC_@@C^C`@@dC_L1Ca@@C_Cb@@+@Ca@XCc@@CaCd@@dCcmHCe@@CcmiCf@B@UX @ p Cg@@ pCh@@ CgCi@@dChZ1Cj@@ChCk@@p@CjCl@@CkCm@@dClRacCn@@ClCo@@@CnCp@@@CoCq@@@CpCr@@tCq1jCs@@Cq2Ct@@Cp\pCu@@CofreqCv@@CnL1Cw@@CjLengthCx@B@UP  g Cy@@ pCz@@CyC{@@dCzZ1C|@@CzC}@@+@C|@XC~@@C|ohmC@B@U g C@@ pC@@CC@@dC Z012_p4_34C@@CC@@+@C@XC@@CCJ0C*@U8)o<8847?- Similarly 7 9 C< C:1C</ C< C0@NormalTimes New Roman C@B@U`H^XC@@ pC@@ CC@@dC GMRbundleC@@{CC@@CC@@dCGMR3C@@CDa1a2C@B@U@J^XC@@ pC@@CC@@dC GMRbundleC@@CC@@+@C@XC@@CftC@B@UHuC@@ pC@@ CC@@dCL1bunC@@CC@@dCIconsC@@CC@@dClnC@@pCC@@CC@@dCDmC@@C GMRbundleC@B@U@lC@@ pC@@CC@@dCL1bunC@@CC@@+@C@XC@@CC@@dCmHC@@CmiC@B@UHcuC@@ pC@@ CC@@dCZ1bunC@@5CC@@p@CC@@CC@@@CC@@dCRac3C@@C2C@@CC@@@CC@@@CC@@@CC@@tC1jC@@C2C@@C\pC@@CfreqC@@CL1bunC@@CLengthC@B@UC@@ pC@@CC@@dCZ1bunC@@CC@@+@C@XC@@CohmC*@U vUj^LeF-A2Consider an untransposed line described in problem 4.4 and Figure P4.4. Let the ground wire be 1/0 ACSR and recalculate the phase impedance matrix Zabc, the sequence impedance matrix Z012, and the unbalance factors. Compare with previous results from problem 4.20 for the same line without the ground wire.7292C<2C:1C</2C<2C0@NormalTimes New Roman C*@U(i|(xoqx-Ground wire data: 79C<C:1C</C<C0@NormalTimes New Roman C@B@U@xC@@ pC@@ CC@@dCRac_gwC@@5CC@@tC0.888C@@CC@@dCohmC@@CmiC*@U-Table B.8, at 25C and 60Hz79C<C:1C</C<C0@NormalTimes New Roman C@B@U@C@@ pC@@ CC@@dCGMR_gwC@@5CC@@tC.00446C@@CftC@B@UHC@@ pC@@ CC@@dC diameter_gwC@@5CC@@tC.398C@@CinC@B@U(R(C@@ pC@@ CC@@dC Rperlength_gwC@@pCC@@0CC@@0ACC@@0ACC@@0ACC@@0ACC@@0ACC@@0ACD@@0ACD@@0ADD@@0ADD@@0ADD@@0ADD@@0ADD@@0ADD@@0ADD@@0ADD @@@DD @@DD @@dD Rac_gwD @@D RdD @@DRdD@@DRdD@@DRdD@@DRdD@@DD@@dDRacD@@DRdD@@DRdD@@DRdD@@DRdD@@CRdD@@CD@@dDRacD@@DRdD@@CRdD@@CRdD@@CRdD@@CRdD@@CD @@dDRacD!@@DRdD"@B@U(D#@@ pD$@@D#D%@@dD$ Rperlength_gwD&@@D$D'@@+@D&@XD(@@D&D)@@dD(ohmD*@@D(mi4J0D+*@U((op-@B@U@BVePD?@@ pD@@@ D?DA@@dD@XgwDB@@5D@DC@@tDB0DD@@DBftDE*@UATP-(horizontal position is at our zero point7(9(DF<(DG:1DH</(DI<(DJ0@NormalTimes New Roman DK*@U(i|(xH-@HNow calculate distance between conductors (be careful of negative signs)7H9HDLReduce to equivalent 3x3 matrix by removing 4th row and column7>9>E=<>E>:1E?</>E@<>EA0@NormalTimes New Roman EB@B@U8OEC@@ pED@@ ECEE@@dEDZaEF@@EDEG@@dEF submatrixEH@@pEFEI@@ EHEJ@@ @EIEK@@ @EJEL@@ @EKEM@@dELZabc_gwEN@@EL0EO@@EK2EP@@EJ0EQ@@EI2ER@B@UxU$ES@@ pET@@ ESEU@@dETZbEV@@ETEW@@dEV submatrixEX@@pEVEY@@ EXEZ@@ @EYE[@@ @EZE\@@ @E[E]@@dE\Zabc_gwE^@@E\0E_@@E[2E`@@EZ3Ea@@EY3Eb@B@U8P Ec@@ pEd@@ EcEe@@dEdZcEf@@EdEg@@dEf submatrixEh@@pEfEi@@ EhEj@@ @EiEk@@ @EjEl@@ @EkEm@@dElZabc_gwEn@@El3Eo@@Ek3Ep@@Ej0Eq@@Ei2Er@B@UxU&Es@@ pEt@@ EsEu@@dEtZdEv@@EtEw@@dEv submatrixEx@@pEvEy@@ ExEz@@ @EyE{@@ @EzE|@@ @E{E}@@dE|Zabc_gwE~@@E|3E@@E{3E@@Ez3E@@Ey3E@B@U8j"E@@ pE@@ EE@@dEZabceqE@@EE@@dEZaE@@EE@@@EE@@dEZbE@@EE@@dEZdE@@KEE@@E1E@@EZcE@B@U82Fi@#E@@ pE@@EE@@dEZabceqE@@EE@@+@E@XE@@EE*@U  w-In problem 4.20 we found:79E<E:1E</E<E0@NormalTimes New Roman E@B@U8z\E@@ pE@@EE@@dEZabcE@@EE@@+@E@XE@@EE*@U (mmrmi-B&Comparing results: (a) The resistance terms are larger, due to folding in the resistance of the ground wire (b) The self inductance terms are smaller (in Xaa, Xbb, Xcc) since the phase conductors are coupling with a grounded conductor that is much closer than the earth. (c) The inductive reactance of the off-diagonal terms are also smaller.7&9&E<&E:1E</&E<&E0@NormalTimes New Roman E*@U 3 *w"-+Now find the symmetrical components matrix:7+9+E<+E:1E</+E<+E0@NormalTimes New Roman E@B@U0,E@@ pE@@ EE@@dE Z012_p4_40E@@EE@@@EE@@@EE@@dEA1E@@KEE@@E1E@@EZabceqE@@EA1E@B@U0BVP-E@@ pE@@EE@@dE Z012_p4_40E@@EE@@+@E@XE@@EE*@U/r{-and earlier we had:79E<E:1E</E<E0@NormalTimes New Roman E@B@U80E@@ pE@@EE@@dE Z012_p4_20E@@EE@@+@E@XE@@EE*@U9H2-CComparing results: (a) The resistance terms are only larger in the zero sequence terms, since the ground conductor only carries zero sequence currents (b) The self inductance terms X1 and X2 are basically the same, but X0 is smaller for the case with the ground wire. Again, coupling to a closer ground conductor. (c) The off-diagonal terms that couple the zero sequence show differences, those that couple positve to negative are essentially the same. (d) So all of the difference seen in the Zabc matrices are basically in the zero sequence related terms. 79>>E<>E:E<E:EEE1E</E<E0@NormalTimes New Roman E*@U -Capacitance Matrix Calculations79E<E:1E</E<E0@NormalTimes New Roman E@B@U(Q5@E@@ pE@@ EE@@dE\e_oE@@5EE@@@EE@@tE8.854E@@EE@@tE10E@@KEE@@E12E@@EE@@dEFE@@EmE@B@U1RF @E@@ pE@@ EE@@dECconsE@@EE@@@EE@@tE2E@@E\pE@@E\e_oE@B@U(jx~IxE@@ pE@@ EE@@dEHaaiE@@EE@@tE2E@@EHaE@B@Uj~xE@@ pE@@EE@@dEHaaiF@@EF@@+@F@XF@@FftF@B@U js~CxF@@ pF@@ FF@@dFHbbiF@@FF@@tF2F @@FHbF @B@Uj~xF @@ pF @@F F @@dF HbbiF@@F F@@+@F@XF@@FftF@B@U({KF@@ pF@@ FF@@dFHcciF@@FF@@tF2F@@FHcF@B@UF@@ pF@@FF@@dFHcciF@@FF@@+@F@XF@@FftF@B@U(JF @@ pF!@@ F F"@@dF!HabiF#@@{F!F$@@F#F%@@@F$F&@@p@F%F'@@F&F(@@dF'HaF)@@F'HbF*@@F%2F+@@F$F,@@p@F+F-@@F,F.@@dF-XaF/@@F-XbF0@@F+2F1@B@U@aF2@@ pF3@@F2F4@@dF3HabiF5@@F3F6@@+@F5@XF7@@F5ftF8@B@U(JF9@@ pF:@@ F9F;@@dF:HaciF<@@{F:F=@@F@@@F=F?@@p@F>F@@@F?FA@@dF@HaFB@@F@HcFC@@F>2FD@@F=FE@@p@FDFF@@FEFG@@dFFXaFH@@FFXcFI@@FD2FJ@B@U@aFK@@ pFL@@FKFM@@dFLHaciFN@@FLFO@@+@FN@XFP@@FNftFQ@B@U(6K0FR@@ pFS@@ FRFT@@dFSHbciFU@@{FSFV@@FUFW@@@FVFX@@p@FWFY@@FXFZ@@dFYHbF[@@FYHcF\@@FW2F]@@FVF^@@p@F]F_@@F^F`@@dF_XbFa@@F_XcFb@@F]2Fc@B@U@"6b0Fd@@ pFe@@FdFf@@dFeHbciFg@@FeFh@@+@Fg@XFi@@FgftFj*@UYlhH~-GMR from table B.879Fk<Fl:1Fm</Fn<Fo0@NormalTimes New Roman Fp@B@U0iFq@@ pFr@@ FqFs@@dFr diameterFt@@5FrFu@@tFt0.721Fv@@FtinFw@B@Ux1Fx@@ pFy@@ FxFz@@dFyrF{@@FyF|@@dF{ diameterF}@@F{2F~@B@UsHF@@ pF@@ FF@@dFLengthF@@5FF@@tF50F@@FmiF@B@U=)`F@@ pF@@ FF@@dFPF@@5FF@@@FF@@tF1F@@FCconsF@@pFF@@0FF@@0AFF@@0AFF@@0AFF@@0AFF@@0AFF@@0AFF@@0AFF@@0AFF@@@FF@@FF@@dFlnF@@pFF@@FF@@dFHcciF@@FrF@@FF@@dFlnF@@pFF@@FF@@dFHbciF@@FDbcF@@FF@@dFlnF@@pFF@@FF@@dFHaciF@@FDacF@@FF@@dFlnF@@pFF@@FF@@dFHbciF@@FDbcF@@FF@@dFlnF@@pFF@@FF@@dFHbbiF@@FrF@@FF@@dFlnF@@pFF@@FF@@dFHabiF@@FDabF@@FF@@dFlnF@@pFF@@FF@@dFHaciF@@FDacF@@FF@@dFlnF@@pFF@@FF@@dFHabiF@@FDabF@@FF@@dFlnF@@pFF@@FF@@dFHaaiF@@FrF@B@UpHq`F@@ pF@@FF@@dFPF@@FF@@+@F@XF@@FF@@dFmF@@FpFCJ0F@B@UkF@@ pF@@ FF@@dF CapperlengthF@@FF@@dFPF@@KFF@@F1F@B@Ud:F@@ pF@@FF@@dF CapperlengthF@@FF@@+@F@XF@@FF@@dFnFF@@FmiF@B@UBV6PF@@ pF@@ FF@@dFCabcF@@FF@@dF CapperlengthF@@FLengthF@B@UBKV%PF@@ pF@@FF@@dFCabcF@@FF@@+@F@XF@@FnFCJ0F*@UX1@@@-A4.34 Consider the line configuration shown in Figure P4.4. Instead of using a single conductor of 336,400 CM ACSR in each phase, with current carrying capacity of 530 amperes, suppose that each phase consists of a two-conductor bundle of two 3/0 ACSR conductors with capacity of 300 amperes/conductor. Let the two conductors of each bundle be seperated by 1.0ft vertically. Compute the capacitance matrix Cabc for the bundled conductor configuration and compare with the previous solution (problem 4.20).79F<F:1F</F<F0@NormalTimes New Roman F*@U 9L H-@CSince 4.20 neglects the ground wire, it will be neglected here too.7C9CFm8G8@@ pG9@@ G8G:@@dG9 RsbundleG;@@{G9G<@@G;G=@@dG<r3G>@@G<Da1a2G?@B@U0{{G@@@ pGA@@ G@GB@@dGA PequivbundGC@@GAGD@@@GCGE@@tGD1GF@@GDCconsGG@@pGCGH@@0GGGI@@0AGHGJ@@0AGIGK@@0AGJGL@@0AGKGM@@0AGLGN@@0AGMGO@@0AGNGP@@0AGOGQ@@@GPGR@@GPGS@@dGRlnGT@@pGRGU@@GTGV@@dGUHcciGW@@GU RsbundleGX@@GOGY@@dGXlnGZ@@pGXG[@@GZG\@@dG[HbciG]@@G[DbcG^@@GNG_@@dG^lnG`@@pG^Ga@@G`Gb@@dGaHaciGc@@GaDacGd@@GMGe@@dGdlnGf@@pGdGg@@GfGh@@dGgHbciGi@@GgDbcGj@@GLGk@@dGjlnGl@@pGjGm@@GlGn@@dGmHbbiGo@@Gm RsbundleGp@@GKGq@@dGplnGr@@pGpGs@@GrGt@@dGsHabiGu@@GsDabGv@@GJGw@@dGvlnGx@@pGvGy@@GxGz@@dGyHaciG{@@GyDacG|@@GIG}@@dG|lnG~@@pG|G@@G~G@@dGHabiG@@GDabG@@GHG@@dGlnG@@pGG@@GG@@dGHaaiG@@G RsbundleG@B@U0#>k8G@@ pG@@ GG@@dGCabc_buG@@GG@@@GG@@dG PequivbundG@@KGG@@G1G@@GLengthG@B@U02Fj@G@@ pG@@GG@@dGCabc_buG@@GG@@+@G@XG@@GnFG*@UyiYj-6Now if we compare the original Cabc with the Cabc_bu: 7696G<6G:1G</6G<6G0@NormalTimes New Roman G@B@U@eG@@ pG@@GG@@dGCabcG@@GG@@+@G@XG@@GnFG*@U  ( ri-AObservations: (1) The self-capacitance terms are larger with the bundled conductors, capacitance is proportional to the natural log of conductor diameter (2) The off-diagonal capacitance terms also increase. However, if we looked at the offdiagonal terms in the P-matrices at the right, we see that they are nearly identical, so the differences in the capacitance matrices are from the inversion.79G<G:G<G:GG<G:GGG1G</G<G0@NormalTimes New Roman G@B@U q G@@ pG@@ GG@@dG C012_p4_20G@@GG@@@GG@@@GG@@dGA1G@@KGG@@G1G@@GCabcG@@GA1G@B@U8   G@@ pG@@ GG@@dG C012_p4_34G@@GG@@@GG@@@GG@@dGA1G@@KGG@@G1G@@GCabc_buG@@GA1G@B@U !`!G@@ pG@@GG@@dG C012_p4_20G@@GG@@+@G@XG@@GnFCJ0G@B@U0?!~!NX!G@@ pG@@ GG@@dGc_1G@@GG@@p@GG@@GG@@@GG@@@GG@@tG2G@@G\pG@@G\e_oG@@GG@@dGlnG@@pGG@@GG@@dGDmG@@GrG@@GLengthG@B@UJ!+^!X!G@@ pG@@GG@@dGc_1G@@GG@@+@G@XG@@GnF3J0G*@U!!!"(-0Note that c_1 does not match the matrix term....7090G<0G:1G</0G<0G0@NormalTimes New Roman G@B@U!~"X"G@@ pG@@GG@@dG C012_p4_34G@@GG@@+@G@XG@@GnFCJ0G@B@UHO""fh"G@@ pG@@ GG@@dGc_1G@@GG@@p@GG@@GG@@@GG@@@GG@@tG2H@@G\pH@@G\e_oH@@GH@@dHlnH@@pHH@@HH@@dHDmH@@H RsbundleH@@GLengthH @B@U8Z"{n"Uh"H @@ pH @@H H @@dH c_1H @@H H@@+@H @XH@@H nF